Identify each function that has a remainder of -3 when divided x+6

a) x^5 + 2x^2 - 30x + 30
b) x^4 + 4x^3 - 21x^2 - 53x + 12
c) x^3 - 10x^2 - 7
d) x^4 + 6x^3 - 10x - 63

D

Step-by-step explanation:

According to remainder theorem, you can know the remainder of these polynomials if you plug in x = -6 into them.

So we will plug in -6 into x of all the polynomials ( A through D) and see which one equals -3.

For A:

For B:

For C:

For D:

The only function that has a remainder of -3 when divided by x + 6 is the fourth one, answer choice D.

idk

step-by-step explanation:

your victory is right around the corner. never give up.

- niki minaj

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584