Write the polynomial function of least degree that has zeros of x=-i and x=1

(x-1)(x^2 + 1)

Step-by-step explanation:

If the polynomial has two roots or zeros, then the least degree it can be is 2. But when x = -i is a root, generally x = i is a root too. Thus the degree here is 3. Using the roots, you can write the polynomial by finding a factor from each. The zeros are the solution to the factor. So if x = 1, it came from the factor x - 1. x = 1 is the solution because x - 1 = 0 is x = 1 solved.

When x = -i, i this is the result of a square root of a negative number. So x had the exponent 2. To write the factor for x = -i, you should write x^2 + 1. When solved x = +/-√-1 = +/- i.

The function is likely (x-1)(x^2 + 1).

entering that problem on the tube might get you an answer

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it