Arectangular parking lot has a perimeter of 820 ft. the area of the parking lot measure sl 42,000 ft2. what is the dimension of the parking lot?

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Step-by-step explanation:

By definition, the perimeter of a rectangle is:

Where:

P is the perimeter, L is the length and W is the width

Also, the area of a rectangle is:

Where L is the length of the base and W is the width.

We know that for this rectangle:

Now we have two equations and two unknowns (L and W)

Then we solve the system.

Now we substitute this relation in the perimeter equation.

Then for W=210:

And for W=200

Answer

EXPLANATION

Let l and w be the dimensions of the parking lot

The perimeter of the parking lot is given by

This implies that

Dividing both sides by 2

Area of the of the parking lot is given by

putting eqn 1 into ran 2

if

then

and also if

then

Hence the dimensions of the parking lot is

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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