With algebra question need
the graph of a logarithmic has a vertical asymptote at x=4 , contains the point (e+4, 1) , and has an x-intercept of 5. which function is graphed?
question options:

f(x) =ln(x−4)

f(x) =ln(x+4)

f(x) =lnx−4

f(x) =lnx+4

The function f(x) = ln(x - 4) is graphed the question options

Step-by-step explanation:

* Lets study the the information of the problem

- The graph of a logarithmic has a vertical asymptote at x=4

* That means the curve gets closer and closer to the vertical line x = 4

  but does not cross it

- It contains the point (e+4, 1)

* That means if we substitute x = e + 4 in the equation the value

 of y will be equal to 1

- It has an x-intercept of 5

* That means if we substitute y = 0 in the equation the value of x

  will be equal to 5

* Lets find the right answer

∵ f(x) = ln(x - 4)

* To find the equation of the asymptote let x - 4 = 0

∵ x - 4 = 0

∴ x = 4

∴ f(x) has a vertical asymptote at x = 4

* Lets check the point (e + 4 , 1) lies on the graph of the f(x)

∵ x = e + 4

∴ f(e+4) = ln(e + 4 - 4) = ln(e)

∵ ln(e) = 1

∴ The point (e+4 , 1) lies on the graph of the function f(x)

* To find the x-intercept put y = 0

∵ f(x) = 0

∴ ln(x - 4) = 0

* Change the logarithmic function to the exponential function

- The base of the ln is e

∴ e^0 = x - 4

∵ e^0 = 1

∴ x - 4 = 1 ⇒ add 4 to the both sides

∴ x = 5

* The function f(x) = ln(x - 4) is graphed the question options

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step-by-step explanation: