Arectangle is 9 ft long and 40 in. wide. what is its area in square feet? (note: 1 ft = 12 in.)
30 ft2
36 ft2
98 ft2
360 ft2

first option

Step-by-step explanation:

Let's make the following conversion:

40 inches to feet (Knowing that 1 feet=12 inches):

The formula for calculate the are of  a rectangle is:

Where l is the lenght and w is the width.

Therefore, when you substitute values, you obtain the following result:

The correct answer is first option 30 ft²

Step-by-step explanation:

Formula:-

Area of rectangle = l x b

l - Length of rectangle

b - Breadth of rectangle

It is given that,A rectangle is 9 ft long and 40 in

To find the area

here l = 9 ft

b = 40 in = 40/12 ft

Area = l x b = 9 x (40/12) = 30 ft²

Area of rectangle =  30 ft²

The correct answer is first option  30 ft²

answer: 32.68

step-by-step explanation:

x=2

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).