Afire insurance company wishes to study the amount of fire damage in major residential fires. the data they collected from a simple random sample of fires in the past six months are shown below: damage (in thousands of dollars) 26.2 17.8 23.1 36.0 31.1 43.2 36.4 26.1 the fire chief wishes to estimate the mean amount of damage with a 95% confidence interval. the population is normally distributed. what is the left bound of the 95% confidence interval for the true population mean (rounded to 2 decimal places)?

23.08 < µ < 36.9

Step-by-step explanation:

First we need to find the sample mean and standard deviation.  

Sample mean:  Add up the values and divide by the total amount of values...

(26.2 + 17.8 + 23.1 + 36.0 + 31.1 + 43.2 + 36.4 + 26.1)/8 = 239.9/8 = 29.99

The sample standard deviation is calculated on the first attached photo

s = 8.27

The confidence interval is constructed in the second attached photo

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.