Find the quotient -5+12i/ 3-3 square root 3i using trigonometric forms

2.433

Step-by-step explanation:

using

a+bi=r(cosP+isinP)

Let

-5 = cosФ

12 = sinФ

Taking square both on both sides

(-5)² + (12)² = cos²Ф +sin²Ф

we know that

sin²Ф + cos²Ф = 1

25 + 144 = (1)

= √(144 + 25)

                      = 13

Similarly,

Let

-3 = cosФ

-3√3 = sinФ

taking square both on both sides

(-3)² + (-3√3)² = cos²Ф +sin²Ф

we know that

sin²Ф + cos²Ф = 1

9 + 27 = (2)

= √(9 + 27)

                      = 6

Also

And

So

=

= 2.433

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral