Ajar contains 4 red marbles, 4 green marbles, and 5 blue marbles.
if we choose a marble, then another marble without putting the first one back in the jar, what is the probability that the first marble will be blue and the second will be green?

20/156 or 5/39

Step-by-step explanation:

the first part of the equation will be:

5/13 (5 is how many blue and 13 is altogether)

the next part of this equation is the green marble. Because we didn't put the blue marble back, the next part of the equation will be:

4/12 (4 is how many green and 12 is altogether now that one blue was taken out)

and from there, you multiply 5/13 with 4/12, with will give you 20/156, or 5/39 if you simplify.

On khan it is 5/39

Step-by-step explanation:

just got it right lol

step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.

i would say b) is your answer

sorry if im wrong

step-by-step explanation: