Given a circle with measures of (c, d, and r) and a circle with measures of (c', d', and r'), what is d if c c' = 12 and d' = 0.50?

d = 6 units

Step-by-step explanation:

Circumference of the circle is given by:

where, d is the diameter of the circle.

As per the statement:

Given a circle 1 with measures of (C, d, and r) and a circle 2 with measures of (C', d', and r').

Circumference of a circle(C) 1 with diameter(d) is given by:

              .....[1]

Also, the circumference of a circle (C') 2 with diameter(d') is given as:

Divide equation [1] and [2] we have;

⇒

Substitute the given values and d' = 0.50 then;

Multiply both sides by 0.50 we have;

6 = d

or

d = 6 units

Therefore, the value of d is, 6 units

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?