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For the triangles just use the equation a^2 + b^2 = c^2. c is the hypotenuse and a and b are the other two sides. if you have at least 2 of the sides you can change the equation to find the other side. Now for the second shape (the weird rectangle-triangle thingy) you just have to do 17-11= 6 witch gives you a. B is already given to you b = 8, so all you have to do is 6^2 + 8^2 witch is 100 then you can square root it with becomes 10. so your x = 10 for that shape.

Step-by-step explanation

You should use a^2 + b^2 = c^2 for the Pythagorean Theorem.

Lets try #1:

5^2 + 12^2 = c^2

That being said, c is for x

5 * 5 + 12 * 12 = 25 + 144 = 169

√169 = c^2

c = 13

So, #1 is x = 13.

Now, you try doing the other problems using the formula.

For #4 use the Pythagorean Theorem twice to find x and y.

Hope this Helped you solve the problem!!

If you need more help you can comment

~A̷l̷i̷s̷h̷e̷a̷♡

there will be 35 boys in each team. : )

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12