Abakery gave out coupons to celebrate its grand opening. each coupon was worth either $1, $3, or $5. twice as many $1 coupons were given out as $3 coupons, and 3 times as many $3 coupons were given as $5 coupons. the total value of all the coupons given out was $360. how many $3 coupons were given out?

54

$3 dollar coupons were given

Step-by-step explanation:

We can represent this question as a system of equations

Let

x = number of $1 dollar coupons

y = number of $3 dollar coupons

z = number of $5 dollar coupons

Twice as many $1 coupons were given out as $3 coupons,

x = 2*y

3 times as many $3 coupons were given as $5 coupons.

y = 3*z

The total value of all the coupons given out was $360

x*$1 + y*$3 + z*$5 = $ 360

The system results

x   -   2y   +  0    =  0         (1)

0   +  y     -  3z    = 0         (2)

x    + 3*y      +5*z =   $ 360    (3)

We substitute  equation (2) and (1) into (3)

(2y)   + 3*y    + 5*(y/3) =   $ 360

20*y/3  = 360

y = 54

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

other answer is correct. i had used the radius of the radius somehow. a website: