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Mathematics, 03.02.2020 00:46 winstonbendariovvygn
Evaluate lim x β 0+ x ln(x3). solution the given limit is indeterminate because, as x β 0+, the first factor (x) approaches 0 correct: your answer is correct. while the second factor ln(x3) approaches ββ. writing x = 1/(1/x), we have 1/x β β as x β 0+, so l'hospital's rule gives lim x β 0+ x ln(x3) = lim x β 0+ ln(x3) 1/x = lim x β 0+ 3/x β1/x2 = lim x β 0+ incorrect: your answer is incorrect. = .
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Evaluate lim x β 0+ x ln(x3). solution the given limit is indeterminate because, as x β 0+, the firs...
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