Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .005 significance level.

the null and alternative hypothesis would be:

h0: pm=pfh0: pm=pf
h1: pm
h0: μm=μfh0: μm=μf
h1: μm> μfh1: μm> μf

h0: pm=pfh0: pm=pf
h1: pm> pfh1: pm> pf

h0: μm=μfh0: μm=μf
h1: μm< μfh1: μm< μf

h0: μm=μfh0: μm=μf
h1: μm≠μfh1: μm≠μf

h0: pm=pfh0: pm=pf
h1: pm≠pfh1: pm≠pf

the test is:

two-tailed

right-tailed

left-tailed

based on a sample of 40 men, 25% owned cats
based on a sample of 40 women, 35% owned cats

the test statistic is: (to 2 decimals)

the p-value is: (to 2 decimals)

based on this we:

fail to reject the null hypothesis

reject the null hypothesis

The null and alternate hypothesis would be

H0:   pm = pf  

H1:   pm < pf  

Test is left tailed

The test statistic: z = -0.98

The p-value: 0.1365

We fail to reject the null hypothesis

Conclusion:  There is not enough evidence to support the claim that the proportion of men who own cats is less than the proportion of women who own cats

Step-by-step explanation:

The null and alternate hypothesis would be

H0:  pm = pf

Ha:  pm < pf    

because they say that the test claim is the proportion of men is smaller less than the proportion of women.  The null hypothesis always get the statement of equality (the equals sign).  In this case, the alternate hypothesis is the claim.  

The test is left tailed because the alternate hypothesis has a <  sign.  It's strictly less than a value, so it's one tailed, and the < or > sign points to the area of rejection, so in this case, it's pointing left

The test statistic is calculation is attached as a photo  

The p-value is found by looking it up on the chart using z = -0.98

Since 0.1365 > 0.005, we fail to reject the null hypothesis

Because we fail to reject the null, there is not enough evidence to support the claim

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629