The scatterplot shows the distance (in feet) that a person was from a motion sensor during an experiment in math class. use the labeled points to create a linear model. about what distance in feet (y) would a person be 8 seconds after the experiment begins?

a.) 21ft
b.) 27ft
c.) 30ft
d.) 57ft

B.) 27ft

Step-by-step explanation:

The labeled points given: (5,18) and (1.5, 7.5)

Slope = (18 - 7.5)/(5-1.5) = 10.5 / 3.5 = 3

A linear model:

y - 18 = 3(x - 5)

y - 18 = 3x - 15

y = 3x + 3

If x = 8 seconds then the distance in feet (y) would be: (plug in x = 8 into the equation y = 3x + 3)

y = 3(8) + 3

y = 24 + 3

y = 27 ft

B.) 27ft

hello 0xxbadwolfxx0,

2.6 x 10^9 is 2,600,000,000.

1.3 x 10^2 is 130

multiplying 130 and 2,600,000,000 would simply give you 200,000,000,000.

therefore, the answer would be d. 2.0 × 10^11.

i hope i ! warm regards, mae.