Iwill award ! ! find the areas of the trapezoids.

A = 10.5 units^2

Step-by-step explanation:

The area of a trapezoid is found by

A = 1/2(b1+b2) *h

b1 = 5

b2 = 2

h = 3

I found these by looking at the graph

A = 1/2(5+2) *3

A =1/2(7)3

A = 10.5 units^2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.