Determine the eccentricity, the type of conic, and the directrix for
r=6/1+2cos theta

Choice C is correct

Step-by-step explanation:

The polar equation of the conic section is in standard form. The eccentricity is simply the coefficient of cos theta; thus e = 2

The eccentricity being more than 1 implies the conic section is a hyperbola.

To determine the directrix, divide 6 by 2 to obtain 3. The conic section opens to the left thus;

directrix; x = 3

whats the question?

step-by-step explanation: