On january 22nd , 2006, kobe bryant scored 81 points against the toronto raptors. including three‐pointers, two‐pointers, and free‐throws he made 46 shots. he made three times as many two‐point shots as three‐point shots. how many free-throws did kobe bryant make?

18

Step-by-step explanation:

x = the number of free throws

y = the number of 2 pointers

z = the number of 3 pointers

x + 2y + 3z = 81

x + y + z = 46

y = 3z

x = 18 free throws

y = 21 two pointers

z = 7 three pointers

Kobe Bryant made 18 free throws.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!