Suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $55. for one performance, 20 advance tickets and 35 same-day tickets were sold. the total amount paid for the tickets was $1700. what was the price of each kind of ticket?

Price of advance ticket: 15$

Price of same-day ticket: $40

Step-by-step explanation:

Let be the price of one advance ticket and the cost of one same day ticket.  

We know that the combined cost of one advance ticket and one same-day ticket is $55, so

equation (1)

We also know that 20 advance tickets and 35 same-day tickets cost $1700, so

equation (2)

Now, let's solve our system of equations step-by-step:

step 1. Solve for in equation (1)

equation (3)

step 2. Replace equation (3) in equation (2)

equation (4)

step 3. Replace equation (4) in equation (3)

We can conclude that the price of one advance ticket is $15 and the price of one same-day ticket is $40.

45

step-by-step explanation:

angle addition postulate

2x=56

step-by-step explanation: