Mathematics, 31.01.2020 20:50 lillygrl100

Compute the value of the following expressions: 323 mod 5 323 div 5 −323 mod 5 −323 div 5 327 mod 3 (64 · (−67) + 201) mod 7 (〖38〗^12) mod 6 (〖38〗^12) mod 3

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Answer from: Cookie320

323 mod 5 = 3

−323 mod 5 = -3

327 mod 3 = 0

(64 * (-67) + 201) mod 7 = 6

(38^12) mod 6 = 4

(38^12) mod 3 = 1

Step-by-step explanation:

The modulo operation looks for remainders from the quotients. In order to find them, divide the whole number by the mod number. Then take just the decimal after the whole answer and multiply it by the mod number.

323 mod 5

323/5 = 64.6

.6 * 5 = 3

−323 mod 5

323/5 = -64.6

-.6 * 5 = -3

327 mod 3

327/5 = 109

0 * 3 = 0

(64 * (-67) + 201) mod 7

64 * -67 = -4288 + 201 = 4087

4087/7 = 583.85714

.85714 * 7 = 6

(38^12) mod 6

38^12 = 9.07x10^18

9.07x10^18/6 = 1510956318082499242.6666667

.666667 * 6 = 4

(38^12) mod 3

38^12 = 9.07x10^18

9.07x10^18/3 = 3021912636164998485.333333

.3333333 * 3 = 1

Answer from: jenn8214p3e8mx

323 mod 5 = 3

−323 mod 5 = -3

327 mod 3 = 0

(64 * (-67) + 201) mod 7 = 6

(38^12) mod 6 = 4

(38^12) mod 3 = 1

Step-by-step explanation:

323 mod 5

323/5 = 64.6

.6 * 5 = 3

−323 mod 5

323/5 = -64.6

-.6 * 5 = -3

327 mod 3

327/5 = 109

0 * 3 = 0

(64 * (-67) + 201) mod 7

64 * -67 = -4288 + 201 = 4087

4087/7 = 583.85714

.85714 * 7 = 6

(38^12) mod 6

38^12 = 9.07x10^18

9.07x10^18/6 = 1510956318082499242.6666667

.666667 * 6 = 4

(38^12) mod 3

38^12 = 9.07x10^18

9.07x10^18/3 = 3021912636164998485.333333

.3333333 * 3 = 1

Answer from: Quest

reduce the friction between its moving parts

step-by-step explanation:

in fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

Answer from: Quest

5x+10 is the correct one

hope this

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Compute the value of the following expressions: 323 mod 5 323 div 5 −323 mod 5 −323 div 5 327 mod 3...