The third term in a sequence is 11.
the term-to-term rule is “take away 4”.
write an expression, in terms of n, for the nth term of the sequence

a(n) = 19 - 4(n-1)

Step-by-step explanation:

The general formula for an arith. seq. is

a(n) = a(1) + (n-1)d, where d is the "term to term rule" or the "common difference," a(1) is the first term and a(n) is the nth term.

Here, a(n) = a(1) - (n-1)(4).

If the 3rd term is 11, then:

a(3) = a(1) - (3-1)(4) = 11, or a(3) = a(1) - 8 = 11

Adding 8 to both sides yields a(1) = 19.

Then the specific expression for the nth term is:

a(n) = 19 - 4(n-1).

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )