The third term in a sequence is 11.
the term-to-term rule is “take away 4”.
write an expression, in terms of n, for the nth term of the sequence

a(n) = 19 - 4(n-1)

Step-by-step explanation:

The general formula for an arith. seq. is

a(n) = a(1) + (n-1)d, where d is the "term to term rule" or the "common difference," a(1) is the first term and a(n) is the nth term.

Here, a(n) = a(1) - (n-1)(4).

If the 3rd term is 11, then:

a(3) = a(1) - (3-1)(4) = 11, or a(3) = a(1) - 8 = 11

Adding 8 to both sides yields a(1) = 19.

Then the specific expression for the nth term is:

a(n) = 19 - 4(n-1).

1. 34

2. 268

3. x=14.4

step-by-step explanation:

the correct answer is c

good luck love