*a turtle and a snail start moving towards each other when they are 200 feet apart. the turtle is running at a speed of t feet per minute, and the snail is moving at a speed of s feet per minute. how soon will they meet?

        200 ft               200

t = = min

      (S + T) ft/min      S + T

Step-by-step explanation:

Recall that distance = (rate)(time).

The distance traveled by the turtle in t minutes is dt = (T ft/min)(t), and

the distance traveled by the snail in t minutes is ds = (S ft/min)(t).  We know that ds + dt must be 200 ft.

Thus,

(S ft/min)(t) + (T ft/min)(t) = 200 ft.

The variable t, representing elapsed time, is common to both terms on the left.  Thus,

        200 ft               200

t = = min

      (S + T) ft/min      S + T

idk

step-by-step explanation:

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places