How do i graph y = x^2 − 6x + 5 ? i really need someone to explain this for me. 59 points

Step-by-step explanation:

We can factor the equation to find the zeros

y = x^2 − 6x + 5

0 =   x^2 − 6x + 5

0 = (x-5) (x-1)

Using the zero product property

x-5 = 0      x-1 =0

x=5   x=1

The zeros are at (1,0) and (5,0)

The vertex is 1/2 way between the zeros

1+5 = 6  6/2 =3

The x coordinate of the vertex is 3

Substituting into the equation

y = 3^2 -6(3) +5

y = 9-18+5

y= -4

The vertex is at (3,-4)

We know it is symmetric around x=3

The y intercept is (0,5)

correct answer:

b.(19,-2)

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)