How do you solve 2cos²(x)-cos(x)=0

Step-by-step explanation:

Start by factoring the left side of 2cos²(x)-cos(x)=0:

cos x [ 2cos x - 1 ] = 0.  

Then cos x = 0 and 2cos x - 1  = 0.

Restricting ourselves to positive angles between 0 and 2π, we get from cos x = 0 the angles x = π/2 and x = 3π/2.

Rewriting 2cos x - 1  = 0, we get

2cos x = 1, or cos x = 1/2.  One solution is x = π/3, in the first quadrant; the other is x = 5π/3, in the fourth quadrant.

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer