15 a store manager receives a delivery
of 2 boxes of lightbulbs. each box
contains 25 lightbulbs. the store
manager tests all the lightbulbs and
finds that 2 of them are defective.
based on these results, what can
the store manager predict about the
next delivery of lightbulbs?
a a delivery of 3 boxes will contain
3 more defective lightbulbs than
a delivery of 2 boxes.
b a delivery of 4 boxes will contain
2 more defective lightbulbs than
a delivery of 2 boxes.
c a delivery of 5 boxes will contain
10 more defective lightbulbs than
a delivery of 2 boxes.
d
a delivery of 6 boxes will contain
3 more defective lightbulbs than
a delivery of 2 boxes.

B

Step-by-step explanation:

For each box, there is 1 defective lightbulb. Therefore, a delivery of 4 boxes will have 4 defective lightbulbs. A delivery of 2 boxes has 2 defective lightbulbs. 4 defective lightbulbs subtracted by 2 defective lightbulbs equals 2 more defective lightbulbs in 4 boxes than 2. Therefore, it is B.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2