What is the range of the function f(x)=3x^2+6-8

The range is all numbers greater than or equal to -11

Step-by-step explanation:

To find the range, we first need to find the vertex. We can find the x value by using -b/2a in which a is the coefficient of x^2 and b is the coefficient of x.

-b/2a

-6/2(3)

-6/6

-1

So the x value is -1 and we can find the y value by plugging that in.

f(x) = 3x^2 + 6x - 8

f(-1) = 3(-1)^2 + 6(-1) - 8

f(-1) = 3(1) - 6 - 8

f(-1) = 3 - 6 - 8

f(-1) = -11

And since it is a positive equation, we know that this is a minimum.

false

step-by-step explanation:

i looked it up

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