Julian fully simplifies this polynomial and then writes it in standard form. 4x2y2 – 2y4 – 8xy3 + 9x3y + 6y4 – 2xy3 – 3x4 + x2y2 if julian wrote the last term as –3x4, which must be the first term of his polynomial in standard form? 4y4 6y4 –2xy3 –10xy3

1st Option is correct.

Step-by-step explanation:

Given Polynomial is

We need to find first term of the polynomial when it is in standard form.

First we simplify it and rewrite it in standard form.

Consider,

First term =

Therefore, 1st Option is correct.

this is not the answer this is just a question. is this middle school math?

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.