There are 11 red checkers and 5 black checkers in a bag. checkers are selected one at a time, with replacement. each time, the color of the checker is recorded. find the probability of selecting a red checker exactly 6 times in 9 selections. show your work.

P(6 times in 9 selection) = 0.116

Step-by-step explanation:

There are 11 red checkers and 5 black checkers in a bag so

P(red) = no. of red checkers / total no. of checkers = 11/(11+5) = 11/16

Checkers are selected one at a time, with replacement. So P(red) is the same for every selection at 11/16.

Use binomial distribution to find the probability of selecting a red checker exactly 6 times in 9 selections.

In this case, n = 9 and k = 6, P(red)=11/16 so

P(6 times in 9 selection) = nCk * P(red)^k * (1-P(red))^(n-k)

where 9C7 = 9! / [7!*(9-7)!] = 9! / 7!*2! = 9*8 / 2 =36

so  P(6 times in 9 selection)

= 36 * (11/16)^6 * (5/16)^3

= 0.116

answer: (1,3) and (-2,0) i think.

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.