Heather has to solve this system of equations using elimination. what should be her first step? 3x+6y = 12 x+5y = 10

Multiply he second equation by -3

The solution is (0, 2)

Step-by-step explanation:

When doing this, you make it so you can eliminate the x variables...

start with

3x + 6y = 12  

 x  + 5y = 10        

Now multiply the second equation by -3

-3(x + 5y = 10) becomes...

 -3x - 15y - 30

Now our system is

3x + 6y = 12

-3x - 15y = -30

When we add them together, we get

  -9y = -18

***The x variable is gone, so we have eliminated that

Here is the final solution in case you need it..

  -9y = -18     solve for y..

      y = 2      (divide by -9 on both sides to isolate y)

There for x is

x + 5(2) = 10

  x + 10 = 10

     x = 0

so the solution is (0, 2)

pooopoopopoopop

step-by-step explanati∵∵∴∴on:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0