The teacher passed out math books. the length is 10 inches and the width is 8 inches. what is the perimeter of each book?

 The perimeter of each book is:  " 36 in. " .

Step-by-step explanation:

Note that the given units are all in "inches (in.)" .

Use the formula for the "perimeter of a rectangle" ;

{which happens to work for a "square" as well;

          since a "square" is a rectangle.}.

This is based on the assumption that the book is shaped like a

"rectangle"  (or "square" —which is a rectangle).

The formula for the Perimeter of a rectangle is:

  P = 2 L  + 2 w  ;

in which:

P =  the perimeter of the rectangle;

for which we shall solve;   [in "inches (in.)" ] ;

L =  the length of the rectangle = 10 in. (given) ;

w = the width of the rectangle = 8 in. (given) .

Now, plug the given values for the "length (L)" and the "width (w)" ;

 as follows:

    P = (2 * 10 in.)  +  (2 * 8 in.)  ;

    P = (20 in.)  +  (16 in.)  ;

   P = 36 in.

 The perimeter of each book is:  " 36 in. " .

Hope this helps!

    Best wishes in your academic pursuits

            — and within the "" community!

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step-by-step explanation: