Given: m∠aoc = 120°, m∠bod = 150°. find: m∠foe.

∠FOE = 90°

Step-by-step explanation:

In this question given is m∠AOC = 120°, m∠BOD = 150°.

We have to calculate ∠FOE.

Since ∠AOB + ∠COD + ∠BOC = 180°  [ Angle at a point on a straight line ]

∠AOB + ∠COD = 180° - ∠BOC ---(1)

It is given ∠AOC = 120° = ∠AOB + ∠BOC (2)

and ∠BOD = 150° = ∠BOC + ∠COD (3)

By adding equation (2) and (3)

150 + 120 = ∠ BOC + ∠COD + ∠AOB + BOC

270 = 2∠BOC + ∠COD + ∠ AOB

Now from equation (1)

270 = 2∠BOC + (180 - ∠BOC)

270 = 180 + ∠BOC

270 -180 = ∠BOC

∠BOC = 90°

Since ∠ BOC ≅ ∠FOE   (opposite angles)

Therefore, ∠FOE = 90° is the answer.

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204