Mathematics, 17.10.2019 11:00 jjjjjjjbvhnchjkj

Find the surface area of the regular hexagonal pyramid. round your answer to the nearest hundredth. a. 69.18 m^2 b. 79.18 m^2 c. 89.18 m^2 d. 99.18 m^2

Find the surface area of the regular hexagonal pyramid. round your answer to the nearest hundredth.

Answers: 3

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Answer from: binodkharal2048

OPTION B

Step-by-step explanation:

Use the following formula:

$SA=\frac{pl}{2}+B$

Where p is the perimeter of the base, l is the slant height and B is the area of the base.

The perimeter is:

p=6*s=6*3m=18m

Where s is the lenght of a side.

The slant height is given:

l=6,2m

The area of the base is:

$B=\frac{3\sqrt{3}s^2}{2}=\frac{3\sqrt{3}(3m)^2}{2}=23.382m^2$

Where s is the length of a side.

Substitute values. Then, the result is:

$SA=\frac{(18m)(6.2m)}{2}+23.382m^2=79.18m^2$

Answer from: 123martinnnnn

The correct answer option is B. 79.18 m^2.

Step-by-step explanation:

We are given a diagram of a regular hexagonal pyramid with height 5.6 m, slant height 6.2 m and base edge length 3m.

We know that the surface area of a regular hexagonal pyramid is given by:

$\frac{PI}{2} +B$

where P = perimeter of the base, I = slant height and B = base area.

Perimeter of base = $3 \times 6$ = 18 m^2

Base area (area of hexagon) = $\frac{3\sqrt{3} }{2} a^2$ = $\frac{3\sqrt{3} }{2} 3^2$ = 23.38 m^2

Surface area of hexagonal pyramid = $\frac{18 \times 6.2}{2} +23.38$ = 79.18 m^2

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Answer from: Quest

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Find the surface area of the regular hexagonal pyramid. round your answer to the nearest hundredth....

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