Iwill award solve
rewrite without absolute value for the given conditions:

1) y=|x−3|+|x+2|−|x−5| , if -2 < x < 3

2) y=|x−3|+|x+2|−|x−5| , 3 < x < 5

1.  x

2. 3x-6

Step-by-step explanation:

1) y=|x−3|+|x+2|−|x−5| , IF -2 < X < 3

|x−3| will be less than zero if -2 < X < 3   so rewrite it as 3-x

|x+2| will be greater than zero if -2 < X < 3  so we can leave it as x+2

|x−5| will be less than zero  if -2 < X < 3 so we rewrite it as 5-x

1. 3-x + x+2  - (5-x)

Combine like terms

5 - (5-x)

Distribute

5 - 5+x

x

1) y=|x−3|+|x+2|−|x−5| , IF 3 < X < 5

|x−3| will be greater than zero if 3 < X < 5   so leave it  as x-3

|x+2| will be greater than zero if 3 < X < 5  so we can leave it as x+2

|x−5| will be less than zero  if -2 < X < 3 so we rewrite it as 5-x

x-3 + x+2  - (5-x)

Combine like terms

2x-1 - (5-x)

Distribute

2x-1 - 5+x

3x-6

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation:

my guess would be b and d, but i didn’t actually get out the pen and paper. lol