The width of a rectangle is 5 units less than the lenght. if the area is 104 square units, then find the dimensions of the rectangle

The length is 13 and width is 8

Let the length is L

Width will be L-5

Area of rectangle = Length x Width

Putting the values

104 = L x L-5

104=l(l−5)

Simplify both sides of the equation.

104=l²−5l

Subtract l²-5l from both sides.

104−(l²−5l)=l²−5l−(l²−5l)

−l²+5l+104=0

Factor left side of equation.

(−l−8)(l−13)=0

Set factors equal to 0.

−l−8=0 or l−13=0

l=−8 or l=13

We will take l = 13 because length cannot be negative

Now for width we know that w = l -5

So width is 13 -5 = 8

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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the answer is (-4,-4)

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