The relationship between voltage, e, current, i, and resistance, z, is given by the equation e = iz. if a circuit has a current i = 3 + 2i and a resistance z = 2 – i, what is the voltage of the circuit? 4 – i
4 + i
8 + i
8 + 7i

The voltage of the circuit is 8 + i

Step-by-step explanation:

∵ E = IZ

∵ I = 3 + 2i

∵ Z = 2 - i

∴ E = (3 + 2i)(2 - i) = 6 - 3i + 4i - 2i²

∴ E = 6 + i - 2(-1) ⇒ i² = -1

∴ E = 6 + i + 2 = 8 + i

18

step-by-step explanation:

ik this stuph and i am smart donkey

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: