Which is the graph of f(x)=2(3)^x?

f(x)= 2(3)^x

putting x = 0

y = f(0) = 2(3)^0= 2

so at x = 0 y should be 2

putting x = 1

y = 2(3)^1 = 6

so at x = 1 y should be 6

select the graph which has these points

so option A is your answer

Option A

(A) first Graph (1,6)

Step-by-step explanation:

you need a common difference between consecutive terms to be constant, like 1,2,3,4 or 2,4,6,8, or 1,3,6,9

c

step-by-step explanation: