The sum of two consecutive odd intergers is more than -12. what is the smallest value that will make the statement true? write an inequality that can be used to find the smallest value that will make the statement true

The smallest value is -8 as a sum of two consecutive odd integers

Which are -5 and -3

Step-by-step explanation:

Let the first odd number is x, then the second odd number is x + 2

∵ The sum of them is more than -12

∴ x + (x + 2) > -12

∴ 2x + 2 > -12

∴ 2x > -12 - 2

∴ 2x > -14 ⇒ ÷ two sides by 2

∴ x > -7

∴ x = {-6 , -5 , -4 , -3 , -2 , -1 , 0 , 1 , }

∵ The numbers are odd

∴ The numbers must be -5 and -3 to give a sum -8 which will make the  

   statement true

∴ The two consecutive odd numbers are -5 , -3

∴ The smallest value is -8

To check:

∵ -5 + -3 = -8

∵ -8 > -12

∴ The statement is true

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right