With reference to the diagram, which conclusion can be drawn correctly from the premises? a) ac = co b) oa + ob + ab > ∠bac c) m∠aco < 45° d) m∠bac = 90°

Applying premise I, OA = OB and OA = OC.

Applying premise II, to ΔOAB, m∠OAB = m∠ABO = m∠ABC.

Applying premise III, to ΔOAC, m∠OAC = ∠ACO = m∠ACB.

Now on application of premise III, it follows that:

2 m∠ABC + 2 m∠ACB = 180° ⇒ m∠ABC + m∠ACB = 90°

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345