Plz figure abcd has vertices a(−4, 1), b(2, 1), c(2, −5), and d(−4, −3). what is the area of figure abcd? (1 point) 24 square units 30 square units 36 square units 45 square units

The area = 30 units²

Step-by-step explanation:

∵ A (-4 , 1) and (2 , 1)

∴ AB is a horizontal segment (same y-coordinates)

∴ AB = 2 - -4 = 6 units

∵ B (2 , 1) and C (2 , -5)

∴ BC is a vertical segment (same x-coordinates)

∴ AB ⊥ BC

∴ BC = 1 - -5 = 6 units

∵ A (-4 , 1) and D (-4 , -3)

∴ AD is a vertical segment

∴ AD ⊥ AB

∴ AD // BC

∴ AD = 1 - -3 = 4 units

∴ ABCD is trapezium with parallel bases AD , BC and height AB

∵

∴ units²

a) justify

step-by-step explanation:

justifying is just part of everyday life. justify kind of means proof so i think the answer is a) justify.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: