Which is not an equation of the line going through (3,6) and (1,-2)?

C is the answer.

Step-by-step explanation:

What you do is you plug the numbers in to the equation according to the x and y.

So we will solve for y.

(3, 6) and (1, -2) is what you will be using. The 3 and 1 are the x and the 6 and -2 are the y.

So lets look at number C. y-2=4(x+1). You will add an x number into the x like this. y-2=4(3+1). You will then do the distributive property to get y-2=12+4.

You will then add 12 and 4 together to get y-2=16. You will then take the 2 and add it to the 16. to get y=18.

See how that doesn't equal 6 or -2 because those are y's. So C is the answer.  

C and D

Step-by-step explanation:

Let's actually find the line going through (3,6) and (1,-2).

As we go from (3, 6) to (1, -2), x decreases by 2 and y decreases by 8.  Thus, the slope of this line is m = rise / run = -8/(-2), or m = 4.

Starting with the point-slope equation of a straight line, y - k = m(x - h), and substituting 4 for the slope, m, we get:

y - k = 4(x - h).

We could use either given point to be the general point (h, k).

If we use the point (3, 6), then y - 6 = 4(x - 3).  This matches B.  Thus, B is one form of the equation of the line going thru  (3,6) and (1,-2), and so B is not the correct answer to the problem you have posted.

If we use the point (1, -2), then y + 2 = 4(x - 1).  This matches A.  Thus, A is one form of the equation of the line going thru  (3,6) and (1,-2), and so A is not the correct answer to the problem you have posted.

Now take a look at Cy - 2 = 4(x + 1).  This can be rewritten as

y = 4x + 4 + 2, or y = 4x + 6.  Does (3, 6) satisfy this equation?

Is 6 = 4(3)  + 6 true?  NO.  Thus, y = 4x + 6 (Equation C) is not an equation of the given line.  Thus, C is a correct answer to the question you have posted.

Finally, let's look at D:  y - 2 = 4(x + 1).  Does the given point (1, -2) satisfy this equation?  Is -2 -2 = 4(1 + 1) true?  Is -4 = 8 true?  NO.  Thus, D is another correct answer to the question you have posted.

ghjmutmum

step-by-step explanation: