What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1 ?

Zero of the function;

f(x) = 0 at x = -1.333

Discontinuity;

x = 1

Step-by-step explanation:

To determine the zero of the function;

we simply graph the function as shown in the attachment below.

From the attachment, we can deduce that f(x) = 0 at x = -1.333

To determine the discontinuity or the undefined points of the function, we simply equate the denominator to 0 and solve for x;

x - 1 =0

x = 1

The function is therefore not defined at the point where x =1

The discontinuity of the given function f(x)= at x=1

and zero of function f(x) is x=-1.33

Step-by-step explanation:

Given function

f(x)=

When we put x=1 then we get an  indeterminate form

f(x)=

f(x)= ( indeterminant form)

Therefore , the function is discontinuous at x=1 .Hence, the discontinuity at x=1.

Now, we find zero of given function by putting f(x)=0

f(x)=0

=0

By splitting middle term of numerator we get

=0

By factorization we get

=0

By simplification we get

=0

x=-1.33

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.