Assume that y varies inversely with x. if y = 16 when x = 1/2, find y when x=32

y varies inversely with x.

Example:

If we multiply x by 2 we need to divide y by 2 too.

So,

If y = 16 and x = 1/2, find y when x = 32

Lets see, from 1/2 to 32 e need to multiply 1/2 by 64, right? So let's divide 16 by 64.

16/64 = 8/32 = 4/16 = 2/8 = 1/4

So we can say that:

If y = 16 when x = 1/2, y = 1/4 when x = 32.

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.