Graph the image of the figure after a dilation with a scale factor of 3 centered at (2,−7) . use the polygon tool to graph the quadrilateral by connecting all its vertices.

  see attached

Step-by-step explanation:

Each point moves 3 times the distance from the center of dilation that it was.

You can compute the new coordinates by ...

  L = P - O . . . . . the length from O to P is P-O for some point P and origin O

Then 3 times that distance is

  3L = 3P -3O

We want to find the point P' that is 3L from O, so we add this distance to the coordinates of O. We get ...

  P' = 3L +O = 3P -3O +O

  P' = 3P -2O

So, for the lower left point A(-2, -7), the dilated image point A' is ...

  A' = 3(-2, -7) -2(2, -7) = (-6, -21) +(-4, 14) = (-10, -7)

That is, ...

  A' = 3A +(-4, 14)

The coordinates of the remaining points can be found similarly.

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On a graph, it is usually fairly easy to count the grid squares in each direction between the point of interest and the center of dilation. The image point is 3 times the distance in each direction (horizontally, vertically).

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

(23*2)-12=x     x=34

step-by-step explanation: