Solve the equation 4c^2 + 7c – 5 = 0 using the quadratic formula

The answer would be:

4c2 + 7c – 5 = 0   a=4   b=7   c=-5

x = [-b +-sq root (b^2 -4ac)] / 2a

x = [-7 +-sq root(7^2 -4*4*-5)] / 2*4

x = [-7 +-sq root(49 + 80)] / 8

x = [-7 +-5.5677643628] /8

x1 = 0.544727125

x2 = -2.294727125

Hope this helps :)

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents