The goals against average (a) for a professional hockey goalie is determined using the formula a=60(g/2). in the formula, g represents the number of goals scored against the goalie and t represents the time played, in minutes. which is an equivalent equation solved for g?
a) at/60=g
b) a/60t=g
c) 60a/t=g
d) 60at=g

g = At/60

Step-by-step explanation:

Given:

A = 60(g/t)  

60(g/2) is a mistake in the question which the question                                        has corrected in the comments)

A is the average for a professional hockey goalie.

g is the number of goals scored against the goalie.

t represents the time played in minutes.

Finding 'g':

A = 60(g/t)

can be written as A = (60*g)/t

Multiplying by 't' on both sides:

At = (60*g)*t/t

At = 60*g

Dividing by '60' on both sides:

At/60 = 60*g/60

At/60 = g

⇒ g = At/60

g=at/60

Step-by-step explanation:

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

no solution

step-by-step explanation:

there is not enough information in the problem to solve.