Identify the x-intercept and y-intercept of the line 4x-2y=-12

First let's put the equation into slope-intercept form...

y= mx + b

4x - 2y = -12
-2y = -4x - 12
y = 2x + 6

In this form, the y intercept is represented by b (in this case 6).

Now if we set y = to zero in the equation, that will give us the x intercept...

0= 2x + 6
-6 = 2x
-3 = x

So we have...
x Intercept = -3
y intercept = 6

X intercept is where the line crosses the x axis or where y=0
y intercept is where the line crosses the y axis or where x=0

x intercept
set y=0 and solve
4x-2(0)=-12
4x=-12
x=-3
(-3,0) is x intercept

y intercept
set x=0 and solve
4(0)-2y=-12
-2y=-12
y=6
(0,6)

xint=(-3,0)
yint=(0,6)

The vertex of the quadratic function is (1.5, -.75)

Im pretty sure it would be 6 purple rectangles.