The average mcat score follows a normal distribution, with a mean of μ = 508 and a standard deviation of σ = 8. what is the probability that the mean iq score of 100 randomly selected people will be more than 510?
0.0062
0.9938
0
0.4013
0.5987

Subtract the mean from the high score and divide by the standard deviation:

510 - 508 = 2

2/8 = 0.25

Using the Z tabe find the z value for 0.25 = 0.5987

Now subtract that value from 1:

1 - 0.5987 = 0.4013

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75