1. find the area of each figure to the nearest tenth.

Answer with step-by-step explanation:

We are given two figure for which we have to find their areas.

To make it easier, we will break down these figure into recognizable shapes and then find the total area.

Figure 1:

Area of rectangle = 110 x 140 = 15400 cm^2

Area of triangle = 0.5 x (180 - 110) x 90 = 3150 cm^2

Area of figure 1 = 15400 + 3150 = 18550 cm^2

Figure 2:

Area of square = 8 x 8 = 64 cm^2

To find the area of triangle, we need to find the length of the base using the Pythagoras Theorem:

Area of triangle = 0.5 x 6 x 8 = 24 cm^2

Area of figure 2 = 64 + 24 = 88 cm^2

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;