Find the prime factorization of each composite number 45

The prime factorization of  45  is   45 = 5 x  3 x  3  OR  5 ⋅ 3 ²

We could also write this as:

5 ⋅ 3 ²

From the multiplication table, we know that  

45 = 5 ⋅x9  where 5  is prime, but  9  is not

 The prime factorization of  9  is  3 ⋅x3 ,

so the prime factorization of 45  is   45 = 5x 3x 3

OR

5 ⋅ 3 ²

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol