Find the point, m, that divides segment ab into a ratio of 3: 2 if a is at (0, 15) and b is at (20, 0).

(12,6)

Step-by-step explanation

The segment is AB

A(0,15) and B(20,0) and ratio is 3:2

To find M we start with point A (0,15),

X coordinate of M is given by;

0+ 3/5 (20-0) where 5 is from the ratio(3+2) and x2-x1is (20-0)

X for M=0+12=12

Doing the same for My 15+3/5(0-15) =15-9=6

M (12,6)