Ryan throws a baseball upward with an initial velocity of 12 m/s from a height of 2m above the ground. how long will it take for the baseball to hit the ground? round answer to the nearest 10th of a second.

It will take 2.6 s for the ball to hit the ground.

Step-by-step explanation:

This is a standard physics problem

The equation that defines the movement of Ryans baseball is given by the initial velocity, and the acceleration

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 2m over the ground)

Vo is the initial velocity = 12m/s

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 )

t is the time

We substitute in the equation, and solve for t (time)

(0)=  2+ (12)*t + 0.5*(-9.8)*t^2

We get that

t = 2.606 s  = 2.6 s

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation: